In C#, data can be converted from one type to another by using an implicit conversion (automatic) or an explicit conversion (we can choose how it’s done).
For the complete navigation of this series check out: C# Back to Basics.
In this article, we are going to cover:
So, let’s talk more about that.
Implicit Conversion in C#
Many different data could be interpreted by using different types. For example, the number 74 can be interpreted as an integer but also as double (74.0). There are two situations in which implicit conversion applies.
The first one is when we calculate an expression. The compiler automatically adapts data types that we use in that expression:
class Program
{
static void Main(string[] args)
{
double b = 12.45;
int x = 10;
b = b + x;
}
}
Here the b variable is of type double and x is of type int. In the expression b + x, the compiler implicitly converts x from int to double and then it assigns a result to the b.
The second situation for conversion is when the compiler stores the result to a variable:
class Program
{
static void Main(string[] args)
{
int y = 20;
int x = 10;
double b;
b = y / x;
}
}
In this example, we see that both x and y are of the type int, but the result is of the type double.
Now, let’s pay attention to this example:
int x = 21; int y = 5 double b = x/y;
What do you think, which value is stored in the variable b?
The answer: “The result is 4.2” is not correct. Of course, now goes the question: “But why”?
The compiler calculates the right-side expression first and only then converts that result into double. So, the right side expression x/yconsist of integer numbers, thus the result is an integer number as well, in this example, it is 4 (the value is truncated). After that calculation, the compiler converts the result into a double and assigns the value to the b variable:
class Program
{
static void Main(string[] args)
{
int y = 5;
int x = 21;
double b = x / y;
}
}
We can fix this if we want, by using the explicit conversion on either x or y variable in the expression.
Explicit Conversion in C#
For the explicit conversion, we need to write additional code to convert one type to another. We have two different ways, by using a cast operator or by using the Convert class.
Let’s look at the following example:
The compiler complains about an invalid conversion. What we are missing here is the cast operator, so let’s use it:
class Program
{
static void Main(string[] args)
{
int a;
double b = 10.7;
a = (int)b;
}
}
By using the cast (int)conversion, we can safely cast our data types and the compiler approves of that. But what we can see is that our result is not what we would expect it to be. But this is the correct result. It is very important to understand that the cast operator can shrink data when we convert the type with the larger value scope to a type with the smaller value scope. Like we did with the double to int conversion for example.
Now we can apply the cast operator on our example from the Implicit Conversion part, to get the right result:
class Program
{
static void Main(string[] args)
{
int x = 21;
int y = 5;
double b = (double)x / y;
}
}
The result is going to be 4.2.
Using the Convert Class in C#
As we said, we can use the Convert class with its static methods, to explicitly convert one base type to another base type:
class Program
{
static void Main(string[] args)
{
int a = 15;
string s = a; // this is not allowed
int c = 15;
string s1 = Convert.ToString(c);
//or
string s2 = c.ToString();
}
}
Conclusion
We have learned about type conversion and how implicit and explicit conversion behaves in C#.
In the next post, we are going to talk about Linear Structures in C#.
Usually explicit and implicit conversions are operators that are defined for these conversions (explicit and implicit keywords). Using Convert class to convert variables cannot be accounted explicit nor implicit conversion in this context.
Thank you for the suggestion. Still, this example will only help the beginners, and I will add another section to seperate it from the explicit conversion.
Note that the example b = x/y may confuse people. The result of x/y is of type int (so truncated) and only then converted to double. E.g. double c = 21/10 will also result in c having a value of 2.0. Maybe worth to call this out.
Hello Jer0enH. Thank you for your note, I believe that this can only help readers to understand conversion better, so we will update this article.